Auger Horsepower and Capacity Reduction

Horsepower Interpolation

Example by Length:

Given: a 34’ horizontal auger, 8” diameter running at 430 rpm, (15% corn) 2,160 bph.

Per the chart, 30’ takes 2.8 hp in 15% corn.

34 / 30 = 1.13

1.13 x 2.8 = 3.16 hp required

Example by Capacity:

Given: The above auger, 8” x 34’ at 430 rpm but instead of 2,160 bph, we need 2,500 bph.

2,500 / 2,160 = 1.16

1.16 x 3.16 = 3.67 hp required

Capacity Reduction Factor

	CAPACITY REDUCTION FACTOR
ANGLE OF INCLINE	CORN & WHEAT	SOYBEANS & SUNFLOWERS
0	1.0	1.0
5	0.98	0.97
10	0.96	0.94
15	0.94	0.90
20	0.92	0.87
25	0.89	0.84
30	0.87	0.80
35	0.85	0.77
40	0.83	0.74
45	0.80	0.70
50	0.77	0.65
55	0.74	0.63
60	0.70	0.60
65	0.67	0.57
70	0.64	0.54
75	0.60	0.50
80	0.57	0.47
85	0.54	0.44
90	0.50	0.40

The horizontal capacity of the equivalent diameter and length of auger can be multiplied by this number to determine the incline capacity at the same horsepower and rpm.